Minimum and Maximum Values for MATH 122
Exam Relevance for MATH 122
Appears in optimization word problems. Finding extrema is the endpoint, not usually tested in isolation.
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What Are Minimum and Maximum Values?
A function has a local maximum at a point if that point is higher than all the nearby points — it's a peak.
A function has a local minimum at a point if that point is lower than all the nearby points — it's a valley.
Together, these are called local extrema (singular: extremum).
Key Definitions
Local Maximum at $x = c$:
$f$ has a local maximum at $c$ if $f(c) \geq f(x)$ for all $x$ in some open interval around $c$.
Local Minimum at $x = c$:
$f$ has a local minimum at $c$ if $f(c) \leq f(x)$ for all $x$ in some open interval around $c$.
Key point: We only compare to nearby points, not the entire domain.
Visualizing Local Extrema
In this graph, notice the function $f(x) = x^3 - 3x$ has:
- A local maximum at $x = -1$ (the peak)
- A local minimum at $x = 1$ (the valley)
At both of these points, the tangent line is horizontal — the slope is zero.
The Connection to Derivatives
At a local maximum or minimum (in the interior of the domain), something special happens:
The tangent line is horizontal — meaning $f'(c) = 0$
This makes sense geometrically:
- Just before a peak, the function is increasing ($f' > 0$)
- Just after a peak, the function is decreasing ($f' < 0$)
- At the exact peak, the slope must be zero ($f' = 0$)
Critical Points: Where to Look
A critical point occurs where:
- $f'(c) = 0$ (horizontal tangent), OR
- $f'(c)$ does not exist (corner, cusp, or vertical tangent)
Important: Not every critical point is a local extremum!
Consider $f(x) = x^3$. Find where $f'(x) = 0$ and determine if there's a local extremum.
Step 1: Find critical points
$$f'(x) = 3x^2$$ $$3x^2 = 0$$ $$x = 0$$
So $f'(0) = 0$. Is $x = 0$ a local max or min?
Step 2: Analyze the behavior
- For $x < 0$: $f(x) = x^3 < 0$
- For $x > 0$: $f(x) = x^3 > 0$
- At $x = 0$: $f(0) = 0$
The function goes from negative to positive, passing through zero. It doesn't have a peak or valley — it just flattens out momentarily!
Step 3: Conclusion
$$\boxed{x = 0 \text{ is NOT a local extremum}}$$
Even though $f'(0) = 0$, the point $(0, 0)$ is neither a local max nor a local min. It's an inflection point where the function levels off but keeps going in the same direction.
Notice how $f(x) = x^3$ has a horizontal tangent at $x = 0$, but it's not a peak or valley — the function is always increasing!
Consider $f(x) = |x|$. Does $f$ have a local minimum at $x = 0$?
At $x = 0$, $f(0) = 0$.
For any $x \neq 0$, $f(x) = |x| > 0$.
So $f(0) \leq f(x)$ for all $x$ near $0$.
$$\boxed{\text{Yes, } f \text{ has a local minimum at } x = 0}$$
Note: Here $f'(0)$ does not exist (the graph has a sharp corner), but it's still a local minimum! Critical points include places where the derivative doesn't exist.
Given that:
- $f'(x) > 0$ for $x < -1$
- $f'(x) < 0$ for $-1 < x < 2$
- $f'(x) > 0$ for $x > 2$
Identify all local extrema.
At $x = -1$: $f'$ changes from positive to negative
- Function goes from increasing to decreasing
- This is a local maximum
At $x = 2$: $f'$ changes from negative to positive
- Function goes from decreasing to increasing
- This is a local minimum
$$\boxed{\text{Local max at } x = -1, \text{ local min at } x = 2}$$
How to Classify Critical Points
| $f'$ changes from... | Type of extremum |
|---|---|
| $+$ to $-$ | Local maximum |
| $-$ to $+$ | Local minimum |
| $+$ to $+$ or $-$ to $-$ | Neither (not an extremum) |
Common Mistakes and Misunderstandings
❌ Mistake: Assuming every critical point is an extremum
Wrong: "$f'(c) = 0$, so there must be a local max or min at $c$."
Why it's wrong: The derivative can be zero at an inflection point where the function just flattens out momentarily.
Example: $f(x) = x^3$ has $f'(0) = 0$, but $x = 0$ is NOT an extremum.
Correct: Check if $f'$ actually changes sign at the critical point.
❌ Mistake: Forgetting about corners and cusps
Wrong: "I set $f'(x) = 0$ and found all the extrema."
Why it's wrong: Local extrema can also occur where $f'$ doesn't exist — at corners or cusps.
Example: $f(x) = |x|$ has a local min at $x = 0$, but $f'(0)$ doesn't exist.
Correct: Check both where $f'(x) = 0$ AND where $f'(x)$ doesn't exist.
Local Maximum Definition
A function has a local maximum at x = c if the function value at c is greater than or equal to function values at all nearby points. The point is a 'peak' in the graph.
Variables:
- $f(c)$:
- The function value at the potential maximum
- $f(x)$:
- Function values at nearby points
- $c$:
- The point where the local maximum occurs
Local Minimum Definition
A function has a local minimum at x = c if the function value at c is less than or equal to function values at all nearby points. The point is a 'valley' in the graph.
Variables:
- $f(c)$:
- The function value at the potential minimum
- $f(x)$:
- Function values at nearby points
- $c$:
- The point where the local minimum occurs
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