Indefinite Integrals for MATH 141
Exam Relevance for MATH 141
Indefinite integrals in MATH 141 are usually part of technique problems rather than standalone questions.
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What is an Indefinite Integral?
An indefinite integral finds a function whose derivative gives you the original function — without evaluating at any specific points. It's also called finding an antiderivative.
Think of derivatives and integrals as opposites:
- Derivative: You have $f(x) = x^2$, and you find $f'(x) = 2x$
- Integral: You have $2x$, and you ask "what function has this as its derivative?" Answer: $x^2$
Integration is like running the derivative "backwards."
Key Notation
The indefinite integral of $f(x)$ is written as:
$$\int f(x) \, dx$$
Where:
- $\int$ — the integral sign (an elongated "S" for "sum")
- $f(x)$ — the integrand (the function you're integrating)
- $dx$ — tells you the variable of integration
The Constant of Integration
Here's something crucial: if $F(x) = x^2$ has derivative $F'(x) = 2x$, then so does:
- $G(x) = x^2 + 5$ → $G'(x) = 2x$
- $H(x) = x^2 - 100$ → $H'(x) = 2x$
- $J(x) = x^2 + \pi$ → $J'(x) = 2x$
Adding any constant doesn't change the derivative! So when we integrate, we must include + C (the constant of integration) to represent all possible antiderivatives:
$$\int 2x \, dx = x^2 + C$$
⚠️ Never forget the +C! It represents a whole family of functions that all have the same derivative.
Basic Integration Rules
These are the "reverse" of differentiation rules you already know.
Power Rule for Integration
$$\int x^n \, dx = \frac{x^{n+1}}{n+1} + C \quad \text{(for } n \neq -1\text{)}$$
Why? Because the derivative of $\frac{x^{n+1}}{n+1}$ is $x^n$.
Constant Multiple Rule
$$\int k \cdot f(x) \, dx = k \int f(x) \, dx$$
Constants can be "pulled out" of the integral.
Sum/Difference Rule
$$\int [f(x) \pm g(x)] \, dx = \int f(x) \, dx \pm \int g(x) \, dx$$
Integrate term by term.
Common Integrals to Memorize
| Function | Integral |
|---|---|
| $\int k \, dx$ | $kx + C$ |
| $\int x^n \, dx$ | $\frac{x^{n+1}}{n+1} + C$ (if $n \neq -1$) |
| $\int \frac{1}{x} \, dx$ | $\ln|x| + C$ |
| $\int e^x \, dx$ | $e^x + C$ |
| $\int \sin x \, dx$ | $-\cos x + C$ |
| $\int \cos x \, dx$ | $\sin x + C$ |
| $\int \sec^2 x \, dx$ | $\tan x + C$ |
Find $\int x^4 \, dx$.
Using the power rule with $n = 4$:
$$\int x^4 \, dx = \frac{x^{4+1}}{4+1} + C = \frac{x^5}{5} + C$$
$$\boxed{\frac{x^5}{5} + C}$$
Find $\int \frac{1}{x^3} \, dx$.
First, rewrite as a power: $\frac{1}{x^3} = x^{-3}$
Now apply the power rule with $n = -3$:
$$\int x^{-3} \, dx = \frac{x^{-3+1}}{-3+1} + C = \frac{x^{-2}}{-2} + C = -\frac{1}{2x^2} + C$$
$$\boxed{-\frac{1}{2x^2} + C}$$
Find $\int (3x^2 - 5x + 2) \, dx$.
Integrate term by term:
$$\int (3x^2 - 5x + 2) \, dx = \int 3x^2 \, dx - \int 5x \, dx + \int 2 \, dx$$
$$= 3 \cdot \frac{x^3}{3} - 5 \cdot \frac{x^2}{2} + 2x + C$$
$$= x^3 - \frac{5x^2}{2} + 2x + C$$
$$\boxed{x^3 - \frac{5x^2}{2} + 2x + C}$$
Find $\int \sqrt{x} \, dx$.
Rewrite the square root as a power: $\sqrt{x} = x^{1/2}$
Apply the power rule with $n = \frac{1}{2}$:
$$\int x^{1/2} \, dx = \frac{x^{1/2 + 1}}{1/2 + 1} + C = \frac{x^{3/2}}{3/2} + C$$
Dividing by $\frac{3}{2}$ is the same as multiplying by $\frac{2}{3}$:
$$= \frac{2}{3}x^{3/2} + C = \frac{2}{3}\sqrt{x^3} + C$$
$$\boxed{\frac{2}{3}x^{3/2} + C}$$
Find $\int \frac{1}{x} \, dx$.
The power rule doesn't work here (we'd get $\frac{x^0}{0}$, which is undefined).
This is a special case that gives us the natural logarithm:
$$\int \frac{1}{x} \, dx = \ln|x| + C$$
We use absolute value $|x|$ because $\ln$ is only defined for positive numbers, but $\frac{1}{x}$ exists for negative $x$ too.
$$\boxed{\ln|x| + C}$$
Find $\int 5e^x \, dx$.
Pull out the constant and use the fact that $e^x$ is its own antiderivative:
$$\int 5e^x \, dx = 5 \int e^x \, dx = 5e^x + C$$
$$\boxed{5e^x + C}$$
Find $\int (2\sin x + 3\cos x) \, dx$.
Integrate term by term using the trig integral formulas:
$$\int (2\sin x + 3\cos x) \, dx = 2\int \sin x \, dx + 3\int \cos x \, dx$$
$$= 2(-\cos x) + 3(\sin x) + C$$
$$= -2\cos x + 3\sin x + C$$
$$\boxed{-2\cos x + 3\sin x + C}$$
True or False: $\int x^2 \, dx = \frac{x^3}{3}$
False. The answer is missing the constant of integration. The correct answer is:
$$\int x^2 \, dx = \frac{x^3}{3} + C$$
Every indefinite integral must include $+ C$ because there are infinitely many functions with the same derivative (they differ by a constant).
True or False: If $F(x)$ and $G(x)$ are both antiderivatives of $f(x)$, then $F(x) - G(x)$ must be a constant.
True. If $F'(x) = f(x)$ and $G'(x) = f(x)$, then:
$$\frac{d}{dx}[F(x) - G(x)] = F'(x) - G'(x) = f(x) - f(x) = 0$$
A function with zero derivative everywhere must be constant. So $F(x) - G(x) = C$ for some constant $C$.
This is why we write $\int f(x) \, dx = F(x) + C$ — all antiderivatives differ by at most a constant!
True or False: $\int \frac{1}{x^2} \, dx = \ln|x^2| + C$
False. This confuses the special case $\int \frac{1}{x} \, dx = \ln|x| + C$ with the general power rule.
For $\frac{1}{x^2} = x^{-2}$, we use the power rule:
$$\int x^{-2} \, dx = \frac{x^{-1}}{-1} + C = -\frac{1}{x} + C$$
The $\ln$ formula only applies when the exponent is exactly $-1$.
Common Mistakes and Misunderstandings
❌ Mistake: Forgetting the +C
Wrong: $\int 2x \, dx = x^2$
Why it's wrong: Without the constant, you're only giving ONE antiderivative. The function $x^2 + 7$ also has derivative $2x$.
Correct: $\int 2x \, dx = x^2 + C$
❌ Mistake: Using the power rule when $n = -1$
Wrong: $\int \frac{1}{x} \, dx = \frac{x^0}{0} + C$ (undefined!)
Why it's wrong: The power rule $\frac{x^{n+1}}{n+1}$ fails when $n = -1$ because you'd divide by zero.
Correct: $\int \frac{1}{x} \, dx = \ln|x| + C$ (memorize this special case!)
❌ Mistake: Wrong sign for trig integrals
Wrong: $\int \sin x \, dx = \cos x + C$
Why it's wrong: The derivative of $\cos x$ is $-\sin x$, not $\sin x$.
Correct: $\int \sin x \, dx = -\cos x + C$
Check: $\frac{d}{dx}(-\cos x) = -(-\sin x) = \sin x$ ✓
❌ Mistake: Confusing integration with differentiation
Wrong: $\int x^3 \, dx = 3x^2 + C$
Why it's wrong: That's the derivative of $x^3$, not the integral! Integration is the reverse process.
Correct: $\int x^3 \, dx = \frac{x^4}{4} + C$
Check: $\frac{d}{dx}\left(\frac{x^4}{4}\right) = \frac{4x^3}{4} = x^3$ ✓
Power Rule for Integration
The fundamental rule for integrating powers of x. Add 1 to the exponent, then divide by the new exponent. Does NOT work when n = -1 (use ln|x| instead).
Variables:
- $n$:
- the exponent (any real number except -1)
- $C$:
- constant of integration
Integral of 1/x
Special case when the power rule doesn't apply. The integral of 1/x is the natural logarithm of the absolute value of x.
Variables:
- $\ln|x|$:
- natural logarithm of the absolute value of x
- $C$:
- constant of integration
Integral of e^x
The exponential function e^x is its own antiderivative. This is one of the simplest integration formulas to remember.
Variables:
- $e^x$:
- the natural exponential function
- $C$:
- constant of integration
Integral of sin(x)
The integral of sine is negative cosine. Note the negative sign!
Variables:
- $C$:
- constant of integration
Integral of cos(x)
The integral of cosine is sine (no negative sign needed).
Variables:
- $C$:
- constant of integration
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